2cos^2(x)+sin(x)cos(x)=1

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Solution for 2cos^2(x)+sin(x)cos(x)=1 equation: 


Simplifying
2cos2(x) + sin(x) * cos(x) = 1

Multiply cos2 * x
2cos2x + sin(x) * cos(x) = 1

Multiply ins * x
2cos2x + insx * cos * x = 1

Multiply insx * cos
2cos2x + cinos2x * x = 1

Multiply cinos2x * x
2cos2x + cinos2x2 = 1

Reorder the terms:
cinos2x2 + 2cos2x = 1

Solving
cinos2x2 + 2cos2x = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Reorder the terms:
-1 + cinos2x2 + 2cos2x = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + cinos2x2 + 2cos2x = 0

The solution to this equation could not be determined.

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